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exercises:2015_ethz_mmm:reaction_energy

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Reaction Energy

In this exercise, you will calculate the reaction energy for the methane combustion reaction: CH4+2O2CO2+2H2O

Reaction energy: EproductsErectants=(2EH2O+ECO2)(ECH4+2EO2)

Ground state oxygen, O2, is a triplet diradical, a property which can explain why liquid oxygen is paramagnetic and attracted to the poles of a magnet.

For this reason, to get the energy of the O2 molecule, a LSD calculation is required.

1.Step

Run a single point calculation for CH4, using the given input file. Note that the file contains explicit basis sets and potential for all-electron calculations. An explanation of the basis set formats is given here: Basis Sets

CH4.inp
&GLOBAL
  PROJECT CH4
  RUN_TYPE ENERGY
  PRINT_LEVEL MEDIUM
&END GLOBAL

&FORCE_EVAL
  METHOD Quickstep              ! Electronic structure method (DFT,...)
  &DFT
    &POISSON                    ! Solver requested for non periodic calculations
      PERIODIC NONE
      PSOLVER  WAVELET          ! Type of solver
    &END POISSON
    &QS                         ! Parameters needed to set up the Quickstep framework
      METHOD GAPW               ! Method: gaussian and augmented plane waves 
    &END QS

    &XC                        ! Parametes needed to compute the electronic exchange potential 
      &XC_FUNCTIONAL NONE      ! No xc functional
      &END XC_FUNCTIONAL
      &HF                      ! Hartree Fock exchange. In this case is 100% (no fraction specified).   
        &SCREENING             ! Screening of the electronic repulsion up to the given threshold.               
          EPS_SCHWARZ 1.0E-10  ! Threshold specification
        &END SCREENING
      &END HF
    &END XC
  &END DFT

  &SUBSYS
    &CELL
      ABC 10 10 10
      PERIODIC NONE              ! Non periodic calculations. That's why the POISSON section is needed 
    &END CELL
    &TOPOLOGY                    ! Section used to center the atomic coordinates in the given box. Useful for big molecules
      &CENTER_COORDINATES
      &END
    &END
    &COORD
  C         4.6425962273        5.0574874650        5.2069537560
  H         5.7240587065        5.0555482951        5.2189766147
  H         4.2766068912        5.8773176685        5.8100567767
  H         4.2759350196        4.1226994019        5.6087492584
  H         4.2938562590        5.1744089096        4.1899119266
    &END COORD
    &KIND H                                      ! potential and basis for H 
      &BASIS   
        3
  1  0  0  3  1
         12.25200000          0.02282200
          1.86870000          0.15564000
          0.41821000          0.48898000
  1  0  0  1  1
          0.10610000          1.00000000
  1  1  1  1  1
          1.00000000          1.00000000
      &END                      
      POTENTIAL ALL
      &POTENTIAL
       1    0    0
       0.20000000    0
      &END 
    &END KIND
    &KIND C                                      ! potential and basis for C
      &BASIS
         5
  1  0  0  6  2
       1252.60000000          0.00557360          0.00000000
        188.57000000          0.04149600         -0.00027440
         42.83900000          0.18263000         -0.00255830
         11.81800000          0.46129000         -0.03337500
          3.55670000          0.44931000         -0.08730500
          0.54258000          0.00000000          0.53415000
  1  0  0  1  1
          0.16058000          1.00000000
  1  1  1  3  1
          9.14260000          0.04449900
          1.92980000          0.23108000
          0.52522000          0.51227000
  1  1  1  1  1
          0.13608000          1.00000000
  1  2  2  1  1
          0.80000000          1.00000000
      &END
      POTENTIAL ALL
      &POTENTIAL
      4    2    0
      0.34883045    0
      &END
    &END KIND

  &END SUBSYS
&END FORCE_EVAL

If the calculation was performed correctly, the total energy of the CH4 molecule is printed in the output file.

 **** **** ******  **  PROGRAM STARTED AT               
 ***** ** ***  *** **   PROGRAM STARTED ON                   
 **    ****   ******    PROGRAM STARTED BY                               
 ***** **    ** ** **   PROGRAM PROCESS ID                                 
  **** **  *******  **  PROGRAM STARTED IN                    

.....

ENERGY| Total FORCE_EVAL ( QS ) energy (a.u.): 

.....

  **** **** ******  **  PROGRAM ENDED AT                 
 ***** ** ***  *** **   PROGRAM RAN ON                       
 **    ****   ******    PROGRAM RAN BY                                  
 ***** **    ** ** **   PROGRAM PROCESS ID                                 
  **** **  *******  **  PROGRAM STOPPED IN           


2.Step

Modify the input in order to perform the same calculation for:

  • H2O
  • CO2
  • O2 triplet
Atomic coordinates for all the molecules, POTENTIAL and BASIS SET for KIND O are given at the end of the exercise.
Remember that the O2 ground state is a triplet state, with non paired electrons. MULTIPLICITY=2S+1=3.

For O2 triplet, the LSD and MULTIPLICITY keywords are needed in the DFT section:

  METHOD Quickstep              
   &DFT                          
     LSD                           ! Requests a spin-polarized calculation for unpaired electrons
     MULTIPLICITY 3                ! Multiplicity = 2S+1 (S= total spin momentum)                      
  ...
  

Another example can be found here Basis Sets

3.Step

At the end, you should get a table like:

Species Total Energy
CH4
O2
H2O
CO2

Now you can compute the overall reaction energy.

Questions

  1. What are the total energies of O2, H2O, CO2, and CH4?
  2. What is the overall reaction energy of the CH4 combustion?
  3. (Optional) What is the total energy difference between the O2 singlet and triplet state?

Appendix

Basis Set for Oxygen

#O  pc-1
  5
  1  0  0  6  2
       2306.70000000          0.00539400          0.00000000
        347.15000000          0.04024800         -0.00031692
         78.89000000          0.17921000         -0.00259440
         21.87600000          0.45978000         -0.03624100
          6.66460000          0.45234000         -0.08779000
          1.06690000          0.00000000          0.53320000
  1  0  0  1  1
          0.30700000          1.00000000
  1  1  1  3  1
         17.02200000          0.04891900
          3.68380000          0.24962000
          0.99234000          0.51347000
  1  1  1  1  1
          0.24487000          1.00000000
  1  2  2  1  1
          1.00000000          1.00000000

Potential for Oxygen

#O ALLELECTRON ALL
    4    4    0
     0.24762086    0

Coordinates for O2

O         4.4720538104        4.7584649515        4.9999999998
O         5.5279461896        5.2415350485        4.9999999995

Coordinates for CO2

  
  C         4.9999776408        4.9999662056        4.9999894728
  O         5.6486993295        5.9339540261        5.0004691016
  O         4.3512530072        4.0659797648        4.9995464311

Coordinates for H2O

  
  O         4.6926974603        4.7525411835        4.6307067609
  H         5.6350172910        4.8022721035        4.7052454388
  H         4.3528571397        5.2445222023        5.3644975249
exercises/2015_ethz_mmm/reaction_energy.1429198162.txt.gz · Last modified: 2020/08/21 10:14 (external edit)